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#61
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The problem of shimmy explained
jim beam writes:
dvt wrote: Similar comments to above. In addition, how would an equally dished wheel be less prone to shimmy? I believe it has been discussed on this newsgroup that dishing *increases* the lateral stiffness of a wheel, that's not right. increasing dish, [reducing angle of the spokes with the rim plane] reduces lateral stiffness. For a given flange spacing, dishing a wheel increases its lateral stiffness. Note that while half the spokes are reduced in bracing angle, the other half are increased, and the effect of the larger angle dominates. -- Joe Riel |
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#62
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The problem of shimmy explained
On Mon, 17 Jul 2006 21:33:33 -0700, jim beam
wrote: jur wrote: jim beam Wrote: jur wrote: If I assume for a moment you are familiar with control theory, then you would understand the meaning of the phrase that the nutation pole is dominant in the loop. Basically it means that it dictates the overall behaviour. Think not of it terms of cause and effect, but of participants. If spinning wheels did not have the tendency towards nutation, where would be no shimmy. Exactly as in placing your hands loosely on the bars. This causes such a massive amount of damping that the nutation pole is no longer dominant. It's still there, but has no dominant effect on behaviour any longer. Undamped, nutation poles have to be taken into account. if they are of a frequency that "feeds" a natural frame/wheel harmonic, yes. but that's the whole point - a system where there is no harmonic is a stable system, nutation poles be damned. Not so. My simplest simulation has only nutation poles and unity gain feedback, and it is unstable. No other poles. Nix. Nada. Frame flex not required. but we're talking manifestation! practical reality is that shimmy can't propagate from microscopic unless it has the freedom to do so, and a resonant frame is that freedom. What caused this "death wobble" shimmy? http://video.google.com/videoplay?do...2751&q=toolbag Doesn't seem like there was enough time for an ocillation to develop. |
#63
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The problem of shimmy explained
R Brickston Wrote: What caused this "death wobble" shimmy? http://tinyurl.com/kxbmg Doesn't seem like there was enough time for an ocillation to develop.Nice example of death wobble. Along the lines of my hypothesis, death wobble requires the following: firm grip on the bars - check. a sudden steering movement to cause a sideways displacement of body mass - check. (bike came down with front wheel at an angle) rider's body gets thrown from side to side, jelly-like, through saddle padding compliance or body compliance - check. Clearly the instability grows exponentially in that vid. -- jur |
#64
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The problem of shimmy explained
In article ,
jur wrote: Tim McNamara Wrote: No, you've just failed to demonstrate your theory as of yet. I will enjoy reading your proofs in hopes of learning something new. I'm looking forward to your discussion with Jobst on this topic, since both of you like to adopt the authoritative tone to quell any disagreement. You are unfortunately making the common error of believing and defending your idea before it's been proven. As others have pointed out, we have seen dozens of guys turn up in the newsgroup shouting "eureka!" only to have reinvented the wheel or to have gotten the wrong end of the stick entirely. So you will have to forgive us if we adopt a wait-and-see attitude towards your breakthrough theory. Saviors come and go all the time. You are assuming an awful lot here. If you thought that i haven't studied all posts here and elsewhere with *close* scrutiny to see if anyone at all has hit on the explanation, well you're just plain wrong. Because of my keen interest in this particular subject, I have studied everything I have come accross which is by now an awful lot. Not added anthing new? Again, you most certainly have not understood at all - you are merely exhibiting you own ignorance and inability to grasp a new concept. (And I know it is Brandt not Brand, just a typo.) Are you at any time going to make a positive contribution? Here's my contribution: Scrutiny Scru"ti*ny (?), n. [L. scrutinium, fr. scrutari to search carefuly, originally, to search even to the rags, fr. scruta trash, trumpery; perhaps akin to E. shred: cf. AS. scrudnian to make scrutiny.] 1. Close examination; minute inspection; critical observation. -- Michael Press |
#65
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The problem of shimmy explained
jur wrote:
Wrote: Is there a reason that you are calling the oscillation of the axis of rotation "nutation" rather than "precession"? This paper discusses the difference between the 2: http://faculty.ifmo.ru/butikov/Applets/Gyroscope.pdf Nutation could be called the high frequency behaviour of precession. Here is another link showing the equations of motion: http://www.gyroscopes.org/math2.asp When I watch those videos of shimmy or death-wobble, I see an oscillation of the axis of rotation of the front wheel, about its normal un-wobbly position. I don't see a second-order oscillation about that first oscillation. Of course, the second order effect could be happening and just be too small for me to see, but then it would not be the primary component of speed wobble. When one does the experiment of hanging a spinning bicycle wheel by one end of the horizontal axle (a common experiment in physics labs), a gravitational torque is exerted by the weight of the wheel about the supported end of the axle, which causes a slow precession of the system about the vertical axis: http://hyperphysics.phy-astr.gsu.edu/HBASE/rotv2.html If then the axle is given a slight whack, the axle should oscillate about the first-order precession. This is nutation and is torque free since (after the initial whack) there is no torque driving the nutation. This is the example at the bottom of http://www.gyroscopes.org/math2.asp. However, it is not the case of the shimmying bicycle wheel. The wheel axle is supported at both fork ends and the force at the axle end is the weight of the bike pushing down. If the bike+rider are perfectly centered over the wheel, there is no torque about the hub center. However, if the bike+rider lean slightly, there is a torque, exerted at the axle ends, which causes the wheel to lean about the forward/back axis ("roll" in aviation terms). Due to the steering geometry of bikes, as the wheel undergoes roll, it also yaws a little. We're all familiar with this, it's how you turn a bike: as the rider leans, the gravity force tilts the bike to one side and exerts a torque on the wheel, which causes the axis of rotation of the wheel to change direction. http://hyperphysics.phy-astr.gsu.edu/hbase/bike.html This is not torque-free. In speed wobble, hands on or off, the system enters an oscillation where some part of the bike+rider tips from side to side rapidly (at least the head tube and bars), causing a torque on the axle which rapidly changes the axis of rotation of the front wheel. I believe it would be more accurate to call this a torque-driven precession than a torque-free nutation. Although the frequency is much faster than we are used to see examples of precession, there is no absolute rule that precession is low frequency and nutation is high. Ben |
#66
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The problem of shimmy explained
I wrote:
We're all familiar with this, it's how you turn a bike: as the rider leans, the gravity force tilts the bike to one side and exerts a torque on the wheel, which causes the axis of rotation of the wheel to change direction. http://hyperphysics.phy-astr.gsu.edu/hbase/bike.html This is not torque-free. Just for clarity, I think that page is oversimplified because it neglects that the lean is initiated by countersteering. Countersteering has been discussed here many times, and an example is shown he http://ist-socrates.berkeley.edu/~fajans/Teaching/Steering.htm But in this context of shimmy, the main point is that leaning a bike exerts a torque on the front wheel to change the direction of the axis of rotation. Ben |
#67
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The problem of shimmy explained
Ben: I think you mis-understood the concept of torque-free nutation. "Torque-free" is only some wording someone has introduced to indicate that a spinning body's spin axis can move without a torque being exerted. It is not a case that if there is torque, then it can't be nutation. Rather, a spinning body will not only precess when torqued, but it will also wobble because a spinning body is an underdamped second order system. Somone has seen fit to call this wobbling/oscillation by a separate name, nutation. "Second order" as used in this context indicates that there is a double-derivative in the differential equation describing the system. See the Damping entry in wikipedia. -- jur |
#68
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The problem of shimmy explained
jur wrote:
dvt Wrote: jur wrote: 'here' (http://en.wikipedia.org/wiki/Speed_wobble) is my explanation in words. I think you're going down the wrong path. I haven't read it all, but here are a few paragraphs from that link that need some attention, IMO. I'm not sure what you mean by wrong path. I already have a complete explanation in mathematical terms which explains everything and takes properly into account nutation which is dominant. Surely you can't mean my explanation is wrong after all that? Surely you aren't assuming I will accept your math without seeing it? This will clearly be shown once I post the model on the wiki entry. Here's my attempt to help: quit spending so much time on these fora and put it towards publishing your math. From what I've seen, you're not improving your credibility by your participation here. | The back wheel will usually be flexing the most since 1) it is not as | stiff as the other components; 2) it is under rider load, so the lower | vertical spokes' tension is reduced, and with a dished wheel the | non-drive side spokes are under even less tension; and 3) it is subject | to a lever action. It requires only a small amount of sideways flexing | to account for the head tube movement. You're saying that the rear wheel stiffness depends on local spoke tension? I don't agree. | All these predict that a stiffer wheel, and an equally dished wheel | will be less prone to shimmy. Double-butted spokes should be more prone | to shimmy, and likewise heavier riders will reduce bottom spoke tension, | increasing shimmy. Similar comments to above. In addition, how would an equally dished wheel be less prone to shimmy? I believe it has been discussed on this newsgroup that dishing *increases* the lateral stiffness of a wheel, which would push the resonant frequency of the system upwards. With stiffness of the wheel I mean the ability of the axle to _twist_ away from the null, not to be displaced sideways _along_ the axis. This mode of stiffness is perhaps different to the lateral one you mean? Yes, I think you are talking about a different stiffness than I was. I'll assume that your "stiffness" refers to the axle rotating away from the perpendicular to the plane of the rim. That's a tough sentence to read; I hope you can parse it. Anyway, my "stiffness" refers to the axle translating axially while remaining perpendicular to the plane of the rim. Neither stiffness will be affected by spoke tension unless the spoke(s) go slack. You should scratch that from your wiki entry. The effect of dish on torsional stiffness is not easily determined; I'd need some proof before I accept your statement as published on the wiki. Have you done the math for the caster effect? I have only shown that it is not required for instabilty; Again, take the time that you're spending on this forum and apply it to your math. I haven't seen your proof that the caster effect is not required, so I can't comment. -- Dave dvt at psu dot edu Everyone confesses that exertion which brings out all the powers of body and mind is the best thing for us; but most people do all they can to get rid of it, and as a general rule nobody does much more than circumstances drive them to do. -Harriet Beecher Stowe, abolitionist and novelist (1811-1896) |
#69
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The problem of shimmy explained
jur wrote:
"Second order" as used in this context indicates that there is a double-derivative in the differential equation describing the system. See the Damping entry in wikipedia. By that definition, any resonance is second order. -- Dave dvt at psu dot edu Everyone confesses that exertion which brings out all the powers of body and mind is the best thing for us; but most people do all they can to get rid of it, and as a general rule nobody does much more than circumstances drive them to do. -Harriet Beecher Stowe, abolitionist and novelist (1811-1896) |
#70
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The problem of shimmy explained
In article ,
jur wrote: jim beam Wrote: jur wrote: If I assume for a moment you are familiar with control theory, then you would understand the meaning of the phrase that the nutation pole is dominant in the loop. Basically it means that it dictates the overall behaviour. Think not of it terms of cause and effect, but of participants. If spinning wheels did not have the tendency towards nutation, where would be no shimmy. Exactly as in placing your hands loosely on the bars. This causes such a massive amount of damping that the nutation pole is no longer dominant. It's still there, but has no dominant effect on behaviour any longer. Undamped, nutation poles have to be taken into account. if they are of a frequency that "feeds" a natural frame/wheel harmonic, yes. but that's the whole point - a system where there is no harmonic is a stable system, nutation poles be damned. Not so. My simplest simulation has only nutation poles and unity gain feedback, and it is unstable. No other poles. Nix. Nada. Frame flex not required. Then every bike would shimmy all the time when ridden hands-off, and that just doesn't happen. You're still making claims without offering proof, giving the appearance of self-inflicted local excavation. I'm still hoping your idea has merit, don't blow it this early in the discussion. |
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